X^2+36x+288=0

Solution for X^2+36x+288=0 equation:

X^2+36X+288=0

a = 1; b = 36; c = +288;
Δ = b2-4ac
Δ = 362-4·1·288
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12}{2*1}=\frac{-48}{2}
=-24
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12}{2*1}=\frac{-24}{2}
=-12
$